Сортирање поређењем — разлика између измена

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Нова страница: {{РАФ2015}} Image:Balance à tabac 1850.JPG|thumb|right|300px|Sorting a set of unlabelled weights by weight using only a balance scale requires a comparison sort a…
 
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The problem of [[X + Y sorting|sorting pairs of numbers by their sum]] is not subject to the {{math|Ω(''n''² log ''n'')}} bound either (the square resulting from the pairing up); the best known algorithm still takes {{math|O(''n''² log ''n'')}} time, but only {{math|O(''n''²)}} comparisons.
 
==Број проређења неопходних за сортирање листе==
==Number of comparisons required to sort a list==
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